Inc num of txs in test mempool
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@ -61,7 +61,7 @@ class PrioritiseTransactionTest (BitcoinTestFramework):
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# 11 kb blocks will only hold about 50 txs, so this will fill mempool with older txs
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taddr = self.nodes[1].getnewaddress()
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for _ in range(300):
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for _ in range(900):
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self.nodes[0].sendtoaddress(taddr, 0.1)
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self.nodes[0].generate(1)
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self.sync_all()
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@ -72,25 +72,25 @@ class PrioritiseTransactionTest (BitcoinTestFramework):
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# Check that priority_tx_0 is not in block_template() prior to prioritisation
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block_template = self.nodes[0].getblocktemplate()
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in_mempool = True
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in_block_template = False
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for tx in block_template['transactions']:
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if tx['hash'] == priority_tx_0:
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in_mempool == False
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in_block_template = True
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break
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assert(in_mempool)
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assert_equal(in_block_template, False)
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priority_result = self.nodes[0].prioritisetransaction(priority_tx_0, 1000, int(3 * base_fee * COIN))
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# Check that prioritized transaction is in getblocktemplate()
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prioritized = False
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in_block_template = False
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block_template = self.nodes[0].getblocktemplate()
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for tx in block_template['transactions']:
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if tx['hash'] == priority_tx_0:
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prioritized = True
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in_block_template = True
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break
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# NOTE: getblocktemplate() should return prioritized transaction, but is not
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# Noted by user in issue #1884
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assert_equal(prioritized, False)
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assert_equal(in_block_template, False)
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# Node 1 doesn't get the next block, so this *shouldn't* be mined despite being prioritized on node 1
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priority_tx_1 = self.nodes[1].sendtoaddress(self.nodes[0].getnewaddress(), 0.1)
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