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Correct generators for BLS12-381.
Signed-off-by: Daira Hopwood <daira@jacaranda.org>
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@ -7235,15 +7235,22 @@ For $i \typecolon \range{1}{2}$, let $\ZeroS{i}$ be the point at infinity in $\S
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and let $\SubgroupSstar{i} := \SubgroupS{i} \setminus \setof{\ZeroS{i}}$.
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\introlist
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Let $\GenS{1} \typecolon \SubgroupSstar{1} := (1, 2)$.
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Let $\GenS{1} \typecolon \SubgroupSstar{1} :=$
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\vspace{-1ex}
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\begin{tabular}{@{}l@{}r@{}l@{}}
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Let $\GenS{2} \typecolon \SubgroupSstar{2} :=\;$
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% are these the right way round?
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&$(11559732032986387107991004021392285783925812861821192530917403151452391805634$ & $\,\mult\, t\;+$ \\
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&$ 10857046999023057135944570762232829481370756359578518086990519993285655852781$ & $, $ \\
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&$ 4082367875863433681332203403145435568316851327593401208105741076214120093531$ & $\,\mult\, t\;+$ \\
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&$ 8495653923123431417604973247489272438418190587263600148770280649306958101930$ & $). $
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\begin{tabular}{@{\tab}r@{}l@{}}
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$($\scalebox{0.81}[1]{$ 3685416753713387016781088315183077757961620795782546409894578378688607592378376318836054947676345821548104185464507$} & $, $ \\
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\scalebox{0.81}[1]{$13395065449444764730204713799419212215849338759383496204265437364165114239563335064727246553533665349923917564415691$} & $)$.
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\end{tabular}
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Let $\GenS{2} \typecolon \SubgroupSstar{2} :=$
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\vspace{-1ex}
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\begin{tabular}{@{\tab}r@{}l@{}}
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$($\scalebox{0.81}[1]{$ 3059144344244213709971259814753781636986470325476647558659373206291635324768958432433509563104347017837885763365758$} & $\,\mult\, t\;+$ \\
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\scalebox{0.81}[1]{$ 352701069587466618187139116011060144890029952792775240219908644239793785735715026873347600343865175952761926303160$} & $, $ \\
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\scalebox{0.81}[1]{$ 927553665492332455747201965776037880757740193453592970025027978793976877002675564980949289727957565575433344219582$} & $\,\mult\, t\;+$ \\
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\scalebox{0.81}[1]{$ 1985150602287291935568054521177171638300868978215655730859378665066344726373823718423869104263333984641494340347905$} & $). $
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\end{tabular}
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$\GenS{1}$ and $\GenS{2}$ are generators of $\SubgroupS{1}$ and $\SubgroupS{2}$ respectively.
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